trigonometry - Proving that $\tan \theta=\cot(90^\circ-\theta
By A Mystery Man Writer
Description
I'm asked to prove $\tan \theta=\cot (90-\theta)$
So $\tan \theta =\frac{a}{b}=\cot(90^\circ-\theta)$
But what if $\theta>90?$
![trigonometry - Proving that $\tan \theta=\cot(90^\circ-\theta](https://i.stack.imgur.com/Q9K5u.jpg)
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